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JEE Main 201815 AprilMorning ShiftOnline
Exam
JEE Main
Year
2018
Date
15 April
Shift
Morning Shift
Mode
Online
Subject
Mathematics
Chapter
Sets and Relations

JEE Main 2018 · 15 April · Morning Shift · Online · Mathematics · Sets and Relations

Consider the following two binary relations on the set A=\ a, b, c\...

Consider the following two binary relations on the set A={a,b,c}:R1={(c,a)(b,b),(a,c),(cA=\{a, b, c\}: R_1=\{(\mathrm{c}, a)(b, b),(\mathrm{a}, c),(c, c),(b,c),(a,a)}c),(b, c),(a, a)\} and R2={(a,b),(b,a),(c,c)\mathrm{R}_2=\{(\mathrm{a}, \mathrm{b}),(\mathrm{b}, \mathrm{a}),(\mathrm{c}, \mathrm{c}), (c, a), (a, a), (b, b), (a, c). Then

Options

  1. AR2R_2 is symmetric but it is not transitive
  2. BBoth R1R_1 and R2R_2 are transitive
  3. CBoth R1R_1 and R2R_2 are not symmetric
  4. DR1R_1 is not symmetric but it is transitive

Correct answer

A. R2R_2 is symmetric but it is not transitive

Step-by-step solution

Both R1R_1 and R2R_2 are symmetric as For any (x,y)∈R1(x, y) \in R_1, we have (y,x)∈R1(y, x) \in R_1 and similarly for R2R_2 Now, for R2,(b,a)∈R2,(a,c)∈R2R_2,(b, a) \in R_2,(a, c) \in R_2 but (b,c)∉R2(b, c) \notin R_2. Similarly, for R1,(b,c)∈R1,(c,a)∈R1R_1,(b, c) \in R_1,(c, a) \in R_1 but (b,a)∉R1(b, a) \notin R_1. Therefore, neither R1R_1 nor R2R_2 is transitive.
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