JEE Main20246 Apr 2024Evening ShiftMathematicsStraight LinesActual
If P (6,1) be the orthocentre of the triangle whose vertices are A (5,-2), B (8,3) and C ( h , k ) , then the point C lies on the circle:
Options
- Ax^2+y^2-61=0
- Bx^2+y^2-52=0
- Cx^2+y^2-65=0
- Dx^2+y^2-74=0
Correct answer
C. x^2+y^2-65=0
Step-by-step solution
Slope of A D=3 Slope of BC =- 1 3 equation of BC =3 y + x -17=0 slope of BE =1 Slope of AC =-1 equation of AC is x + y -3=0 point C is (-4,7)