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JEE Main 20245 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
5 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Straight Lines

JEE Main 2024 · 5 April · Evening Shift · Mathematics · Straight Lines

Let A(-1,1) and B(2,3) be two points and P be a variable point...

Let A(−1,1)A(-1,1) and B(2,3)B(2,3) be two points and PP be a variable point above the line ABA B such that the area of △PAB\triangle \mathrm{PAB} is 10 . If the locus of P\mathrm{P} is ax+by=15\mathrm{a} x+\mathrm{b} y=15, then 5a+2 b5 \mathrm{a}+2 \mathrm{~b} is :Let A(-1,1) and B(2,3) be two points and P be a variable point above the line A B such that the area of PAB is 10 . If

Options

  1. A6
  2. B−65-\frac{6}{5}
  3. C4
  4. D−125-\frac{12}{5}

Correct answer

D. −125-\frac{12}{5}

Step-by-step solution

Let A(-1,1) and B(2,3) be two points and P be a variable point above the line A B such that the area of PAB is 10 . If
12∣hk1−111231∣=10−2x+3y=25−65x+95y=15a=−65, b=955a=−6,2 b=185\begin{aligned} & \frac{1}{2}\left|\begin{array}{ccc}\mathrm{h} & \mathrm{k} & 1 \\ -1 & 1 & 1 \\ 2 & 3 & 1\end{array}\right|=10 \\ & -2 \mathrm{x}+3 \mathrm{y}=25 \\ & -\frac{6}{5} \mathrm{x}+\frac{9}{5} \mathrm{y}=15 \\ & \mathrm{a}=-\frac{6}{5}, \mathrm{~b}=\frac{9}{5} \\ & 5 \mathrm{a}=-6,2 \mathrm{~b}=\frac{18}{5}\end{aligned}
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