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JEE Main20244 Apr 2024Morning ShiftMathematicsStraight LinesActual

The vertices of a triangle are A (-1,3), B (-2,2) and C (3,-1) . A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :

Options

  1. Ax+y+(2- 2 )=0
  2. B-x+y-(2- 2 )=0
  3. Cx+y-(2- 2 )=0
  4. Dx-y-(2+ 2 )=0

Correct answer

C. x+y-(2- 2 )=0

Step-by-step solution

equation of AC x + y =2 equation of line parallel to AC x + y = d aligned & | d -2 2 |=1 & ~d =2- 2 aligned eq ^ n of new required line x + y =2- 2

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