JEE Main202429 Jan 2024Evening ShiftMathematicsStraight LinesActual
Let A be the point of intersection of the lines 3 x + 2 y = 14 , 5 x - y = 6 and B be the point of intersection of the lines 4 x + 3 y = 8 , 6 x + y = 5 . The distance of the point P ( 5 , - 2 ) from the line A B is
Options
- A13 2
- B8
- C5 2
- D6
Correct answer
D. 6
Step-by-step solution
Solving lines L 1 ( 3 x + 2 y = 14 ) and L 2 ( 5 x - y = 6 ) . ⇒ x = 14 - 2 y 3 = 6 + y 5 ⇒ 70 - 10 y = 18 + 3 y ⇒ 52 = 13 y ⇒ y = 4 ⇒ x = 14 - 8 3 = 2 ⇒ A ≡ 2 , 4 Now, solving lines L 3 ( 4 x + 3 y = 8 ) and L 4 ( 6 x + y = 5 ) ⇒ x = 8 - 3 y 4 = 5 - y 6 ⇒ 48 - 18 y = 20 - 4 y ⇒ 28 = 14 y ⇒ y = 2 ⇒ x = 8 - 6 4 = 1 2 ⇒ B ≡ 1 2 , 2 So, equation of A B is given by, A B : y - 4 = 2 - 4 1 2 - 2 x - 2 ⇒ A B : y - 4 = 4 3 x - 2 ⇒ A B : y - 4 = 4 3 x - 2 ⇒ 3 y - 12 = 4 x - 8 ⇒ 4 x - 3 y + 4 = 0 The distance of P 5 , - 2 fr