JEE Main202227 Jul 2022Evening ShiftMathematicsStraight LinesActual
The equations of the sides A B , B C and C A of a triangle A B C are 2 x + y = 0 , x + p y = 39 and x - y = 3 respectively and P 2 , 3 is its circumcentre. Then which of the following is NOT true
Options
- AA C 2 = 9 p
- BA C 2 + p 2 = 136
- C32 < area ∆ A B C < 36
- D34 < area ∆ A B C < 38
Correct answer
D. 34 < area ∆ A B C < 38
Step-by-step solution
Intersection of 2 x + y = 0   &   x - y = 3 is A 1 , - 2 Perpendicular bisector of A B is y - 3 = 1 2 x - 2 ⇒ x - 2 y + 4 = 0 Take image of A along the perpendicular bisector of A B , we get x - 1 1 = y + 2 - 2 = - 2 9 5 = - 18 5 i.e. x = - 13 5 ,   y = 26 5 B - 13 5 , 26 5 This point lies on the line x + p y = 39 i.e. - 13 5 + p 26 5 = 39 ⇒ - 1 + 2 p = 15 ⇒ p = 8 Solving x + 8 y = 39 and x - y = 3 , we get C 7 , 4 Now A C 2 = 1 - 7 2 + - 2 - 4 2 = 72 = 9 p and A C 2 + p 2 = 72