JEE Main202227 Jun 2022Morning ShiftMathematicsStraight LinesActual
In an isosceles triangle A B C , the vertex A is 6 , 1 and the equation of the base B C is 2 x + y = 4 . Let the point B lie on the line x + 3 y = 7 . If α , β is the centroid ∆ A B C , then 15 α + β is equal to
Options
- A51
- B39
- C41
- D49
Correct answer
A. 51
Step-by-step solution
In △ A B C ,   A B = A C Solving 2 x + y = 4   &   x + 3 y = 7 , we get B ≡ 1 , 2 Let C ≡ h , k and as it lies on 2 x + y = 4 so 2 h + k = 4 Now, A B 2 = A C 2 26 = ( h - 6 ) 2 + k - 1 2 ⇒ 26 = h - 6 2 + 3 - 2 h 2 ⇒ 26 = 5 h 2 - 24 h + 45 ⇒ h - 1 5 h - 19 = 0 ⇒ h = 19 5 (as h = 1 rejected) so k = - 18 5 Hence, centroid = 6 + 1 + 19 5 3 , 1 + 2 - 18 5 3 ≡ 18 5 , - 1 5 i.e. 15 α + β = 15 × 17 5 = 51