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JEE Main 202124 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Evening Shift
Subject
Mathematics
Chapter
Straight Lines

JEE Main 2021 · 24 February · Evening Shift · Mathematics · Straight Lines

Let a point P be such that its distance from the point (5, 0) is...

Let a point PP be such that its distance from the point \left(5, 0\right)isthricethedistanceofis thrice the distance ofPfromthepoint(−5,0).from the point \left(- 5, 0\right) . If the locus of the point PP is a circle of radius r,r, then 4r24{r}^{2} (in the nearest integer) is equal to __________.

Correct answer

0

Step-by-step solution

Let point is (h,k)\left(h, k\right)

So, (h−5)2+k2=3(h+5)2+k2\sqrt{{\left(h - 5\right)}^{2} + {k}^{2}} = 3\sqrt{{\left(h + 5\right)}^{2} + {k}^{2}}

8x2+8y2+100x+200=08{x}^{2} + 8{y}^{2} + 100x + 200 = 0

x2+y2+252x+25=0{x}^{2} + {y}^{2} + \dfrac{25}{2}x + 25 = 0

r2=(25)242−25{r}^{2} = \dfrac{{\left(25\right)}^{2}}{{4}^{2}} - 25

4r2=2524−1004{r}^{2} = \dfrac{{25}^{2}}{4} - 100

4r2=156.25−1004{r}^{2} = 156 . 25 - 100

4r2=56.254{r}^{2} = 56 . 25

After round off 4r2=564{r}^{2} = 56

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