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JEE Main201912 Apr 2019Evening ShiftMathematicsStraight LinesActual

A straight line L at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to this line makes an angle of 60 ° with the line x + y = 0 . Then an equation of the line L is: Note: In actual JEE Main paper, two options were correct for this question. Hence, we have changed one option.

Options

  1. A3 + 1 x + 3 - 1 y = 8 2
  2. Bx + 3 y = 8
  3. C3 x + y = 8
  4. D3 - 1 x + 3 y = 8 2

Correct answer

A. 3 + 1 x + 3 - 1 y = 8 2

Step-by-step solution

Hence, equation of required line using normal form is x c o s 15 ° + y s i n 15 ° = 4 or x c o s 75 ° + y s i n 75 ° = 4 ⇒    ( 3 + 1 ) x + ( 3 - 1 ) y = 8 2 or    ( 3 - 1 ) x + ( 3 + 1 ) y = 8 2

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