JEE Main2013MathematicsStraight LinesActual
If the three lines x-3 y=p, a x+2 y=q and a x+y=r form a right-angled triangle then :
Options
- Aa^2-9 a+18=0
- Ba^2-6 a-12=0
- Ca^2-6 a-18=0
- Da^2-9 a+12=0
Correct answer
A. a^2-9 a+18=0
Step-by-step solution
Since three lines x-3 y=p , a x+2 y=q and a x+y=r form a right angled triangle product of slopes of any two lines =-1 Suppose a x+2 y=q and x-3 y=p are to each other. -a 2 1 3 =-1 a=6 Now, consider option one by one a=6 satisfies only option (a) Required answer is a^2-9 a+18=0