JEE Main2010MathematicsStraight LinesActual
The line L given by x 5 + y b =1 passes through the point (13,32) . The line K is parallel to L and has the equation x c + y 3 =1 . Then the distance between L and K is
Options
- A17
- B17 15
- C23 17
- D23 15
Correct answer
C. 23 17
Step-by-step solution
Slope of line L=- b 5 Slope of line K =- 3 c Line L is parallel to line k . b 5 = 3 c bc =15 (13,32) is a point on L . aligned & 13 5 + 32 b =1 32 b =- 8 5 & b =-20 c =- 3 4 & aligned Equation of K: y-4 x=3 Distance between L and K = |52-32+3| 17 = 23 17