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JEE Main2009MathematicsStraight LinesActual

The lines p (p^2+1 ) x-y+q=0 and (p^2+1 )^2 x+ (p^2+1 ) y+2 q=0 are perpendicular to a common line for

Options

  1. Ano value of p
  2. Bexactly one value of p
  3. Cexactly two values of p
  4. Dmore than two values of p

Correct answer

B. exactly one value of p

Step-by-step solution

Lines must be parallel, therefore slopes are equal p (p^2+1 )=- (p^2+1 ) p=-1

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