JEE Main2006MathematicsStraight LinesActual
A straight line through the point A(3, 4) is such that its intercept between the axes is bisected at A. Its equation is
Options
- Ax + y = 7
- B3x − 4y + 7 = 0
- C4x + 3y = 24
- D3x + 4y = 25
Correct answer
C. 4x + 3y = 24
Step-by-step solution
The equation of axes is x y=0 the equation of the line is x 4+y 3 2 =12 4 x+3 y=24