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JEE Main2002MathematicsStraight LinesActual

A triangle with vertices (4, 0), (-1, -1), (3, 5) is

Options

  1. Aisosceles and right angled
  2. Bisosceles but not right angled
  3. Cright angled but not isosceles
  4. Dneither right angled nor isoceles

Correct answer

A. isosceles and right angled

Step-by-step solution

A B= (4+1)^2+(0+1)^2 = 26 ; B C= (3+1)^2+(5+1)^2 = 52 C A= (4-3)^2+(0-5)^2 = 26 ; So, in isosceles triangle A B=C A For right angled triangle BC ^2= AB ^2+ AC ^2 So, here B C= 52 or B C^2=52 or ( 26 )^2+( 26 )^2=52 So, given triangle is right angled and also isosceles

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