Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202225 Jul 2022Morning ShiftMathematicsThree Dimensional GeometryActual

Let P be the plane containing the straight line x - 3 9 = y + 4 - 1 = z - 7 - 5 and perpendicular to the plane containing the straight lines x 2 = y 3 = z 5 and x 3 = y 7 = z 8 . If d is the distance of P from the point 2 , - 5 , 11 , then d 2 is equal to

Options

  1. A147 2
  2. B96
  3. C32 3
  4. D54

Correct answer

C. 32 3

Step-by-step solution

Let < a , b , c > be direction ratios of plane containing the line x 2 = y 3 = z 5 and x 3 = y 7 = z 8 Since plane normal will be perpendicular to given lines then by condition of perpendicular lines, 2 a + 3 b + 5 c = 0   . . . . 1 and 3 a + 7 b + 8 c = 0 . . . . . 2 On solving 1   &   2 we get, a 24 - 35 = b 15 - 16 = c 14 - 9 So, DR of plane are < 11 , 1 , - 5 > Now let DR of plane P be < a 1 , b 1 , c 1 > Then, 11 a 1 + b 1 - 5 c 1 = 0   . . . . 3 And 9 a 1 - b 1

Practice Three Dimensional Geometry on Quantrex Academy →

More from Three Dimensional Geometry

Let P be the plane such that it contains the straight line x-1 2 = y-3 3 = z+2 1 and is perpendicular to the plane x + 2y + 3z = 4 . Let P₁ be the plane which passes through the po 2026Let L be the straight line joining the points P(1, 2, -1) and Q(2, 3, 1) . Let S be the foot of the perpendicular drawn from the point R(4, -1, 5) to the line L . Another line pass 2026Let the foot of perpendicular from the point ( , 2, 3) on the line x-4 1 = y-9 2 = z-5 1 be the point (1, , 2) . Then the distance between the lines x-1 2 = y-2 3 = z+4 6 and x- 2 2026Let a line L₁ pass through the origin and be perpendicular to the lines L₂: r = (3+t) i + (2t-1) j + (2t+4) k and L₃: r = (3+2s) i + (3+2s) j + (2+s) k , t, s R . If (a, b, c) , a 2026The shortest distance between the lines x-4 1 = y-3 2 = z-2 -3 and x+2 2 = y-6 4 = z-5 -5 is : 2026Let the image of the point P(0, -5, 0) in the line x-1 2 = y 1 = z+1 -2 be the point R and the image of the point Q (0, -1 2 , 0 ) in the line x-1 -1 = y+9 4 = z+1 1 be the point S 2026Let the image of the point P(1, 6, a) in the line L: x 1 = y-1 2 = z-a+1 b , b > 0 , be ( a 3 , 0, a+c ) . If S( , , ) , > 0 , is the point on L such that the distance of S from th 2026Let a line L be perpendicular to both the lines L₁: x+1 3 = y+3 5 = z+5 7 and L₂: x-2 1 = y-4 4 = z-6 7 . If is the acute angle between the lines L and L₃: x - 8 7 2 = y - 4 7 1 = 2026 Full Three Dimensional Geometry list All JEE Main PYQs