JEE Main202118 Mar 2021Morning ShiftMathematicsThree Dimensional GeometryActual
The equation of the planes parallel to the plane x - 2 y + 2 z - 3 = 0 which are at unit distance from the point 1 ,   2 ,   3 is a x + b y + c z + d = 0 . If ( b - d ) = K ( c - a ) , then the positive value of K is
Correct answer
4
Step-by-step solution
Let plane parallel to given plane is x - 2 y + 2 z + λ = 0 Distance from 1 ,   2 ,   3 = 1 ⇒ | λ + 3 | 5 = 1 ⇒ λ = 0 , - 6 On comparing with given equation ⇒ a = 1 , b = - 2 , c = 2 , d = - 6 or 0 b - d = 4 or - 2 ,   c - a = 1 ⇒ K = 4 or - 2