JEE Main2014MathematicsThree Dimensional GeometryActual
Equation of the plane which passes through the point of intersection of lines x - 1 3 = y - 2 1 = z - 3 2 and x - 3 1 = y - 1 2 = z - 2 3 and has the largest distance from the origin is:
Options
- A4 x + 3 y + 5 z = 50
- B3 x + 4 y + 5 z = 49
- C5 x + 4 y + 3 z = 57
- D7 x + 2 y + 4 z = 54
Correct answer
A. 4 x + 3 y + 5 z = 50
Step-by-step solution
Line L 1 : x - 1 3 = y - 2 1 = z - 3 2 = λ L 2 : x - 3 1 = y - 1 2 = z - 2 3 = μ ⇒    x = 3 λ + 1 and x = μ + 3        y = λ + 2   y = 2 μ + 1         z = 2 λ + 3   z = 3 μ + 2 ⇒ 3 λ + 1 = μ + 3 ⇒ 3 λ - μ = 2 λ + 2 = 2 μ + 1 ⇒ λ - 2 μ = - 1 2 λ + 3 = 3 μ + 2 ⇒ 2 λ - 3 μ = - 1 Solving μ = 1 ,   λ