JEE Main2012MathematicsThree Dimensional GeometryActual
The equation of a plane containing the line x+1 -3 = y-3 2 = z+2 1 and the point (0,7,-7) is
Options
- Ax+y+z=0
- Bx+2 y+z=21
- C3 x-2 y+5 z+35=0
- D3 x+2 y+5 z+21=0
Correct answer
A. x+y+z=0
Step-by-step solution
The equation of the plane containing the line x+1 -3 = y-3 2 = z+2 1 is a (x+1)+b(y-3)+c(z+2)=0 where -3 a+2 b+c=0 This passes through (0,7,-7) aligned & a(0+1)+b(7-3)+c(-7+2)=0 & a+4 b-5 c=0 ...(B) aligned On solving equation (A) and (B) we get a=1, b=1, c=1 Required plane is aligned & x+1+y-3+z+2=0 & x+y+z=0 aligned