JEE Main2009MathematicsThree Dimensional GeometryActual

Let the line x-2 3 = y-1 -5 = z+2 2 lies in the plane x+3 y- z+ =0 . Then ( , ) equals

Options

A(6,-17)
B(-6,7)
C(5,-15)
D(-5,15)

Correct answer

B. (-6,7)

Step-by-step solution

Dr's of line =(3,-5,2) Dr's of normal to the plane =(1,3,- ) Line is perpendicular to normal 3(1)-5(3)+2(- )=0 3-15-2 =0 2 =-12 =-6 Also (2,1,-2) lies on the plane aligned & 2+3+6(-2)+ =0 =7 & ( , )=(-6,7) aligned

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