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JEE Main2007MathematicsThree Dimensional GeometryActual

If (2,3,5) is one end of a diameter of the sphere x^2+y^2+z^2-6 x-12 y-2 z+20=0 , then the coordinates of the other end of the diameter are

Options

  1. A(4,9,-3)
  2. B(4,-3,3)
  3. C(4,3,5)
  4. D(4,3,-3)

Correct answer

A. (4,9,-3)

Step-by-step solution

Coordinates of centre (3,6,1) Let the coordinates of the other end of diameter are ( , , ) then +2 2 =3, +3 2 =6, +5 2 =1 Hence =4, =9 and =-3 .

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