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JEE Main2004MathematicsThree Dimensional GeometryActual

The intersection of the spheres x^2+y^2+z^2+7 x-2 y-z=13 and x^2+y^2+z^2-3 x+3 y+4 z=8 is the same as the intersection of one of the sphere and the plane

Options

  1. Ax-y-z=1
  2. Bx-2 y-z=1
  3. Cx-y-2 z=1
  4. D2 x-y-z=1

Correct answer

D. 2 x-y-z=1

Step-by-step solution

Required plane is S₁-S₂=0 where S₁=x^2+y^2+z^2+7 x-2 y-z-13=0 and aligned & S₂=x^2+y^2+z^2-3 x+3 y+4 z-8=0 & 2 x-y-z=1 aligned

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