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The radius of the circle in which the sphere x^2+y^2+z^2+2 x-2 y-4 z-19=0 is cut by the plane x+2 y+2 z+7=0 is

Options

  1. A4
  2. B1
  3. C2
  4. D3

Correct answer

D. 3

Step-by-step solution

centre of sphere =(-1,1,2) Radius of sphere 1+1+4+19 =5 Perpendicular distance from centre to the plane OC = d = | -1+2+4+7 1+4+4 |= 12 3 =4 AC ^2= AO ^2- OC ^2=5^2-4^2=9 AC =3

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