JEE Main2016MathematicsTrigonometric EquationsActual
Let P = θ : sin θ - cos θ = 2 cos θ and Q = θ : sin θ + cos θ = 2 sin θ , be two sets. Then
Options
- AP ⊂ Q and Q - P   ≠   ϕ
- BQ ⊄ P
- CP = Q
- DP ⊄ Q
Correct answer
C. P = Q
Step-by-step solution
P :   sin θ - cos θ =   2 cos θ ⇒ sin θ = cos θ +   2 cos θ tan θ =   2 + 1 Q : sin θ + cos θ =   2 sin θ ⇒ 2 - 1 sin θ = cos θ     = tan θ =   1 2 - 1 =   2 + 1