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Let P = θ : sin θ - cos θ = 2 cos θ and Q = θ : sin θ + cos θ = 2 sin θ , be two sets. Then

Options

  1. AP ⊂ Q and Q - P   ≠   ϕ
  2. BQ ⊄ P
  3. CP = Q
  4. DP ⊄ Q

Correct answer

C. P = Q

Step-by-step solution

P :   sin θ - cos θ =   2 cos θ ⇒ sin θ = cos θ +   2 cos θ tan θ =   2 + 1 Q : sin θ + cos θ =   2 sin θ ⇒ 2 - 1 sin θ = cos θ     = tan θ =   1 2 - 1 =   2 + 1

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