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JEE Main202127 Aug 2021Morning ShiftPhysicsAlternating CurrentActual

The alternating current is given by, i = 42 sin 2 π T t + 10 A . The R.M.S. value of this current is __________ A .

Correct answer

0

Step-by-step solution

The given function of current is, i = 42 sin 2 π T t + 10   A It means, i 2 = 42 sin 2 2 π t T + 100 + 20 42 sin 2 π t T ⇒ i 2 = 42 2 + 100 RMS value of the current is, i r m s = i 2 = 121 = 11   A

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