In the above circuit, C = 3 2 μ F ,   R 2 = 20 Ω ,     L = 3 10 H and R 1 = 10 Ω . Current in L - R 1 path is I 1 and in C - R 2 path it is I 2 . The voltage of AC source is given by, V = 200 2   sin ( 100   t ) volts. The phase difference between I 1 and I 2 is:

Step-by-step solution

Inductive reactance X L = ω L = 100 3 10   Ω = 10   3   Ω Capacitive reactance X c = 1 ω C = 1 100 × 3 2 × 10 - 6   Ω = 20000 3   Ω For i 1 , phase difference between i 1 & voltage t a n ϕ 1   = x L R = 10 3 10 = 3 ⇒   ϕ 1   =   60 o ,   current lagging For i 2 , phase difference t a n ϕ 2 = X C R = 20000 3 × 20 = 1000 3 ⇒    ϕ 1   ≈   90 o ,  &#82