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JEE Main20268 April 2026Evening ShiftPhysicsCapacitanceActual

A parallel plate capacitor is having separation between plates 0.885 mm. It has a capacitance of 1 , F when the space between the plates is filled with an insulating material of resistivity 1 10¹³ , m and resistance 17.7 10¹⁴ , . Relative permittivity of the insulating material is 10^7 . The value of is ________. (Take permittivity of free space =8.85 10⁻¹² F/m)

Correct answer

0

Step-by-step solution

The resistance of the insulating material is given by R = d A . The capacitance of the parallel plate capacitor is given by C = ₀ _r A d . Multiplying the expressions for R and C , we get: RC = ₀ _r Rearranging for relative permittivity _r : _r = RC ₀ Substituting the given values: _r = 17.7 10¹⁴ 10⁻⁶ 10¹³ 8.85 10⁻¹² _r = 17.7 10^8 8.85 10^1 _r = 2 10^7 Comparing this with the given expression _r = 10^7 , we get: = 2 Answer: 2

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