JEE Main20262 April 2026Morning ShiftPhysicsCapacitanceActual
The dimensional formula of 1 2 ₀ E^2 ( ₀ = permittivity of vacuum and E = electric field) is M^a L^b T^c . The value of 2a - b + c = _______.
Options
- A0
- B1
- C-1
- D2
Correct answer
B. 1
Step-by-step solution
The quantity 1 2 ₀ E^2 represents the energy density of an electric field. Energy density is defined as energy per unit volume. Dimensional formula of energy is [M L^2 T⁻²] . Dimensional formula of volume is [L^3] . Dimensional formula of energy density = [M L^2 T⁻²] [L^3] = [M L⁻¹ T⁻²] . Comparing this with M^a L^b T^c , we get: a = 1 b = -1 c = -2 The value of 2a - b + c = 2(1) - (-1) + (-2) = 2 + 1 - 2 = 1 . Answer: 1