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JEE Main202528 Jan 2025Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual

A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

Options

  1. A190 ~g
  2. B200 ~g
  3. C300 ~g
  4. D290 ~g

Correct answer

A. 190 ~g

Step-by-step solution

aligned & _ Net =0 (400 ~g 30)=(250 ~g 10)( mg 50) & m = 12000-2500 50 = 9500 50 & M =190 ~g aligned

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