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JEE Main 20244 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
4 April
Shift
Evening Shift
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JEE Main 2024 · 4 April · Evening Shift · Physics · Center of Mass, Momentum and Collision

In a system two particles of masses m_1=3 ~kg and m_2=2 ~kg are...

In a system two particles of masses m1=3 kgm_1=3 \mathrm{~kg} and m2=2 kgm_2=2 \mathrm{~kg} are placed at certain distance from each other. The particle of mass m1m_1 is moved towards the center of mass of the system through a distance 2 cm2 \mathrm{~cm}. In order to keep the center of mass of the system at the original position, the particle of mass m2m_2 should move towards the center of mass by the distance _____ cm\mathrm{cm}.

Correct answer

0

Step-by-step solution

ΔXC.O.M. =m1Δx1+m2Δx2m1+m2⇒0=3×2+2(−x)3+2⇒x=3cm\begin{aligned} & \Delta \mathrm{X}_{\text{C.O.M. }}=\frac{\mathrm{m}_1 \Delta \mathrm{x}_1+\mathrm{m}_2 \Delta \mathrm{x}_2}{\mathrm{ m}_1+\mathrm{m}_2} \\ & \Rightarrow 0=\frac{3 \times 2+2(-\mathrm{x})}{3+2} \\ & \Rightarrow \mathrm{x}=3 \mathrm{ cm}\end{aligned}
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