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JEE Main20241 Feb 2024Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

A simple pendulum of length 1 m has a wooden bob of mass 1 kg . It is struck by a bullet of mass 10 - 2 kg moving with a speed of 2 × 10 2 m s - 1 . The bullet gets embedded into the bob. The height to which the bob rises before swinging back is. (use g = 10 m s - 2 )

Options

  1. A0 . 30 m
  2. B0 . 20 m
  3. C0 . 35 m
  4. D0 . 40 m

Correct answer

B. 0 . 20 m

Step-by-step solution

Linear momentum will be conserved, therefore m u = M + m V ⇒ 10 − 2 × 2 × 10 2 ≅ 1 × V ⇒ V ≅ 2 m s - 1 Again from energy conservation, we get height achieved, h = V 2 2 g = 0 .2 m .

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