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JEE Main202430 Jan 2024Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

A spherical body of mass 100 g is dropped from a height of 10 m from the ground. After hitting the ground, the body rebounds to a height of 5 m . The impulse of force imparted by the ground to the body is given by: (given g = 9 . 8 m s - 2 )

Options

  1. A4 . 32 kg m s - 1
  2. B43 . 2 kg m s - 1
  3. C23 . 9 kg m s - 1
  4. D2 . 39 kg m s - 1

Correct answer

D. 2 . 39 kg m s - 1

Step-by-step solution

Using equation of motion with constant acceleration, we can write: v 1 = 2 g h 1 and v 2 = 2 g h 2 Now, required impulse I → = Δ p → = p → f - p → i Given, M = 0 . 1 kg Therefore, I = Δ p = 0 . 1 ( 2 × 9 . 8 × 5 - ( - 2 × 9 . 8 × 10 ) ) = 0 . 1 ( 7 2 + 14 ) ≈ 2 . 39 kg m s - 1

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