A spherical body of mass 100g is dropped from a height of 10m from...

Using equation of motion with constant acceleration, we can write:

${v}_{1} = \sqrt{2g{h}_{1}}$ and ${v}_{2} = \sqrt{2g{h}_{2}}$

Now, required impulse

$\overset{\to}{I} = \Delta\overset{\to}{p} = \overset{\to}{p}f - \overset{\to}{p}i$

Given, $M = 0 . 1kg$

Therefore,

$I = \Deltap = 0 . 1 ( \sqrt{2 \times 9 . 8 \times 5} - ( - \sqrt{2 \times 9 . 8 \times 10} ) )$

$= 0 . 1 ( 7\sqrt{2} + 14 ) \approx 2 . 39kgm{s}^{- 1}$