JEE Main 202225 JulyEvening Shift
- Exam
- JEE Main
- Year
- 2022
- Date
- 25 July
- Shift
- Evening Shift
- Subject
- Physics
- Chapter
- Center of Mass, Momentum and Collision
JEE Main 2022 · 25 July · Evening Shift · Physics · Center of Mass, Momentum and Collision
Three identical spheres each of mass M are placed at the corners of...
Three identical spheres each of mass are placed at the corners of a right angled triangle with mutually perpendicular sides equal to each. Taking point of intersection of mutually perpendicular sides as origin, the magnitude of position vector of centre of mass of the system will be . The value of is
Correct answer
0
Step-by-step solution
The diagram represents the locations of the masses as mentioned in the question.
For point , \overset{\to}{{r}_{1}} = 0\overset{^}{i} + 0\overset{^}{j} for point , \overset{\to}{{r}_{2}} = 3\overset{^}{i} + 0\overset{^}{j} and for point , \overset{\to}{{r}_{3}} = 0\overset{^}{i} + 3\overset{^}{j}.
The formula for centre of mass is
⇒ \overset{\to}{r}com = \dfrac{M\left(0\overset{^}{i} + 0\overset{^}{j}\right) + M\left(3\overset{^}{i}\right) + M\left(3\overset{^}{j}\right)}{3M}
⇒ \overset{\to}{r}com = \overset{^}{i} + \overset{^}{j}
\left|\overset{\to}{r}com\right| = \sqrt{{1}^{2} + {1}^{2}} = \sqrt{2} = \sqrt{x}⇒ x = 2