Two billiard balls of mass 0 . 05kg each moving in opposite...

After collision, the balls change their directions of motion without changing the magnitudes of their velocity.

Change in momentum of any one ball

$\left|\Delta\overset{\to}{p}\right| = 2 \times 0 . 05 \times 10$

$⇒ \left|\Delta\overset{\to}{p}\right| = 1kgm{s}^{- 1}$

The force exerted on the ball is \left|\overset{\to}{F}av\right| = \dfrac{\left|\Delta\overset{\to}{p}\right|}{\Deltat} = \dfrac{1}{0 . 005}$</p><p>${F}_{av} = 200N