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JEE Main202225 Jul 2022Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual

Two billiard balls of mass 0 . 05 kg each moving in opposite directions with 10 ms - 1 collide and rebound with the same speed. If the time duration of contact is t = 0 . 005 s , then what is the force exerted on the ball due to each other?

Options

  1. A100   N
  2. B200   N
  3. C300   N
  4. D400   N

Correct answer

B. 200   N

Step-by-step solution

After collision, the balls change their directions of motion without changing the magnitudes of their velocity. Change in momentum of any one ball Δ p → = 2 × 0 . 05 × 10 ⇒ Δ p → = 1   kg   m   s - 1 The force exerted on the ball is F → av   = Δ p → Δ t = 1 0 . 005 F av   = 200   N

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