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JEE Main202117 Mar 2021Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual

The disc of mass M with uniform surface mass density σ is shown in the figure. The center of mass of the quarter disc (the shaded area) is at the position x a 3 π , x a 3 π where x is _______ . (Round off to the Nearest Integer) [ a is an area as shown in the figure]

Correct answer

0

Step-by-step solution

C.O.M of quarter disc is at 4 a 3 π , 4 a 3 π = 4

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