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JEE Main20198 Apr 2019Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

If 10 22 gas molecules each of mass 10 - 26 kg collides with a surface (perpendicular to it) elastically per second over an area 1 m 2 with a speed 10 4 m / s , the pressure exerted by the gas molecules will be of the order of:

Options

  1. A2 P a
  2. B4 P a
  3. C6 P a
  4. D8 P a

Correct answer

A. 2 P a

Step-by-step solution

Total momentum transferred in one second = n 2 m v = 10 22 2 × 10 - 26 × 10 4 = 2 Force experienced by surface = 2 N Pressure on surface = F o r c e A r e a = 2 1 = 2 P a

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