JEE Main 20198 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 8 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Center of Mass, Momentum and Collision
JEE Main 2019 · 8 April · Morning Shift · Physics · Center of Mass, Momentum and Collision
Four particles A, B, C and D with masses m _ A = m, m _ B = 2m, m _...
Four particles and with masses and are at the corners of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the centre of mass of the particles is:

Options
- A\dfrac{a}{5}\left(\overset{^}{i} + \overset{^}{j}\right)
- B\dfrac{a}{5}\left(\overset{^}{i} - \overset{^}{j}\right)
- Ca\left(\overset{^}{i} + \overset{^}{j}\right)
- DZero
Correct answer
B. \dfrac{a}{5}\left(\overset{^}{i} - \overset{^}{j}\right)
Step-by-step solution
\overset{\to}{a}A = - a\overset{^}{i}
\overset{\to}{a}B = a\overset{^}{j}
\overset{\to}{a}C = a\overset{^}{i}
\overset{\to}{a}D = - a\overset{^}{j}
\overset{\to}{a}cm = \dfrac{- ma\overset{^}{i} + 2ma\overset{^}{j} + 3ma\overset{^}{i} - 4ma\overset{^}{j}}{10m}
= \dfrac{2ma\overset{^}{i} - 2ma\overset{^}{j}}{10,} = \dfrac{a}{5}\overset{^}{i} - \dfrac{a}{5}\overset{^}{j} = \dfrac{a}{5}\left(\overset{^}{i} - \overset{^}{j}\right)