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JEE Main 20188 April
Exam
JEE Main
Year
2018
Date
8 April
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JEE Main 2018 · 8 April · Physics · Center of Mass, Momentum and Collision

The mass of a hydrogen molecule is 3.32 × 10 ^ - 27 kg . If 10 ^ 23...

The mass of a hydrogen molecule is 3.32×10−27kg.3.32 \times {10}^{- 27}kg . If 1023{10}^{23} hydrogen molecules strike, per second, a fixed wall of the area 2cm22{cm}^{2} at an angle of 45o{45}^{o} to the normal, and rebound elastically with a speed of 103ms−1,{10}^{3}m{s}^{- 1}, then the pressure on the wall is nearly:The mass of a hydrogen molecule is 3.32 × 10 ^ - 27 kg . If 10 ^ 23 hydrogen molecules strike, per second, a fixed wall

Options

  1. A4.70×102Nm−24.70 \times {10}^{2}N{m}^{- 2}
  2. B2.35×103Nm−22.35 \times {10}^{3}N{m}^{- 2}
  3. C4.70×103Nm−24.70 \times {10}^{3}N{m}^{- 2}
  4. D2.35×102Nm−22.35 \times {10}^{2}N{m}^{- 2}

Correct answer

B. 2.35×103Nm−22.35 \times {10}^{3}N{m}^{- 2}

Step-by-step solution

The mass of a hydrogen molecule is 3.32 × 10 ^ - 27 kg . If 10 ^ 23 hydrogen molecules strike, per second, a fixed wall

F=2mnVcosθF = 2mnVcos\theta⇒P=2mnVcosθA⇒ P = \dfrac{2mnVcos\theta}{A}

⇒P=2×3.32×10−27×1023×1032×2×10−4⇒ P = \dfrac{2 \times 3.32 \times {10}^{- 27} \times {10}^{23} \times {10}^{3}}{\sqrt{2} \times 2 \times {10}^{- 4}}

⇒P=2.35×103Nm−2⇒ P = 2.35 \times {10}^{3}N{m}^{- 2}

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