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JEE Main 202228 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
28 July
Shift
Evening Shift
Subject
Physics
Chapter
Communication System

JEE Main 2022 · 28 July · Evening Shift · Physics · Communication System

A FM Broad cast transmitter, using modulating signal of frequency...

A FM Broad cast transmitter, using modulating signal of frequency 20kHz20kHz has a deviation ratio of 1010. The Bandwidth required for transmission is :

Options

  1. A220kHz220kHz
  2. B180kHz180kHz
  3. C360kHz360kHz
  4. D440kHz440kHz

Correct answer

D. 440kHz440kHz

Step-by-step solution

Given

FM broadcast

Modulating frequency =20kHz=f= 20kHz = f

Deviation ratio =frequencydeviationmodulatingfrequency=∆ff= \dfrac{frequencydeviation}{modulatingfrequency} = \dfrac{∆ f}{f}

⇒⇒ Frequency deviation, \Deltaf=f×10\Deltaf = f \times 10

=20kHz×10=200kHz= 20kHz \times 10 = 200kHz

⇒⇒ Bandwidth =2(f+\Deltaf)= 2\left(f + \Deltaf\right)

=2(20+200)kHz= 2\left(20 + 200\right)kHz

=440kHz= 440kHz

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