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JEE Main202127 Jul 2021Evening ShiftPhysicsCommunication SystemActual

The maximum amplitude for an amplitude modulated wave is found to be 12 V while the minimum amplitude is found to be 3 V . The modulation index is 0 . 6 x where x is _____.

Correct answer

0

Step-by-step solution

A max = A c + A m = 12 A min = A c - A m = 3 ⇒ A c = 15 2 and   A m = 9 2 Modulation index = A m A c = 9 2 15 2 = 0 . 6 ⇒ x = 1

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