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A carrier wave V C ( t ) = 160 sin 2 π × 10 6 t volts is made to vary between V max = 200   V and V min = 120   V by a message signal V m ( t ) = A m sin 2 π × 10 3 t volts. The peak voltage A m of the modulating signal is,

Correct answer

40

Step-by-step solution

Maximum amplitude, A max = A m + A C ⇒ V max = V m + V C 200 = V m + 160 V m = 40 ∴ Peak voltage A m = 40 Answer is 40 .

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