An amplitude modulated signal is given by V ( t )=10[1+0.3 . (2.2 10⁴ t ) ] (5.5 10⁵ t ) . Here t is in seconds. The sideband frequencies (in kHz ) are, [Given =22 / 7 ]

Step-by-step solution

Equation given array l V ( t )=10 [1+0.3 (2.2 10⁴ ) ] (5.5 10⁵ t ) =10+1.5 [ (57.2 10⁴ t )+ (52.8 10⁴ t ) ] _ c + _ w =57.2 10⁴=2 f ₁ array f ₁= 57.2 10⁴ 2 ( 22 7 ) =9.1 10⁴ 91 KHz _ c - _ w =52.8 10⁴ f ₂= 52.8 10⁴ 2 ( 22 7 ) 84 KHz Upper side band frequency (f₁ ) is f ₁= f _ c - f _ w = 52.8 10⁴ 2 85.00 kHz Lower side band frequency ( f ₂ ) is f ₂= f _ c + f _ w = 57.2 10⁴ 2 90.00 kHz