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JEE Main 20178 AprilOnline
Exam
JEE Main
Year
2017
Date
8 April
Mode
Online
Subject
Physics
Chapter
Communication System

JEE Main 2017 · 8 April · Online · Physics · Communication System

A signal of frequency 20kHz and peak voltage of 5Volt is used to...

A signal of frequency 20kHz20kHz and peak voltage of 5Volt5Voltis used to modulate a carrier wave of frequency 1.2MHz1 . 2MHzand peak voltage 25Volts25Volts. Choose the correct statement.

Options

  1. AModulation index =5= 5, side frequency bands are at 1400kHzand1000kHz1400kHzand1000kHz.
  2. BModulation index=5= 5, side frequency bands are at 21.2kHzand18.8kHz21 . 2kHzand18 . 8kHz.
  3. CModulation index =0.2= 0 . 2, side frequency bands are at 1220kHzand1180kHz1220kHzand1180kHz.
  4. DModulation index =5= 5, side frequency bands are at 24.2kHzand18.8kHz24 . 2kHzand18 . 8kHz.

Correct answer

C. Modulation index =0.2= 0 . 2, side frequency bands are at 1220kHzand1180kHz1220kHzand1180kHz.

Step-by-step solution

Modulation index defines the modulated signal's ratio of maximum to minimum voltage

=VmVc=525=0.2= \dfrac{{V}_{m}}{{V}_{c}} = \dfrac{5}{25} = 0.2
Carrier Frequency 1.2×103kHz1.2 \times {10}^{3}kHz

fc=1200kHz{f}_{c} = 1200kHz.

Lower side-band frequency, f1=1200−20=1180KHz{f}_{1} = 1200 - 20 = 1180KHz.

Upper band frequency, f2=1200+20=1220KHz{f}_{2} = 1200 + 20 = 1220KHz.

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