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JEE Main 20154 April

Exam: JEE Main
Year: 2015
Date: 4 April
Subject: Physics
Chapter: Communication System

JEE Main 2015 · 4 April · Physics · Communication System

A signal of 5kHz frequency is amplitude modulated on a carrier wave...

A signal of $5kHz$ frequency is amplitude modulated on a carrier wave of frequency $2MHz$ . The frequencies of the resultant signal is/are:

Options

A $2000kHz\text{and}1995kHz$
B $2MHz\text{only}$
C $2005kHz\text{and}1995kHz$
D $2005kHz, 2000kHz\text{and}1995kHz$

Correct answer

D. $2005kHz, 2000kHz\text{and}1995kHz$

Step-by-step solution

Frequency of signal wave

= 5\text{kH}\text{z} = \text{f}

. Carrier wave frequency

= 2MHz

= 2000 kHz = {\text{f}}_{\text{c}}

. The resultant signal maximum frequency

= \text{f} + {\text{f}}_{\text{c}}

= 5 + 2 0 0 0 kHz

= 2 0 0 5 kHz

Resultant signal minimum frequency

= {f}_{c} - f

= 2 0 0 0 - 5 \text{kHz}

= \text{1995 kHz}

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