Given the electric field of a complete amplitude modulated wave as E = i E_c(1+(E_m)/(E_c) ω_ m t) ω_c t Where the subscript c stands for the carrier wave and m for the modulating signal. The frequencies present in the

Correct answer: B. ω_c, ω_c+ω_m and ω_c-ω_m The frequencies present in amplitude modulated wave are : Carrier frequency =ω_c Upper side band frequency =ω_c+ω_m Lower side band frequency =ω_c-ω_m .

JEE Main 201219 MayOnline

Exam: JEE Main
Year: 2012
Date: 19 May
Mode: Online
Subject: Physics
Chapter: Communication System

JEE Main 2012 · 19 May · Online · Physics · Communication System

Given the electric field of a complete amplitude modulated wave as...

Given the electric field of a complete amplitude modulated wave as

\vec{E}=

\hat{i} E_c\left(1+\frac{E_m}{E_c} \cos \omega_

m t\right) \cos \omega_c t Where

the subscript c stands for the carrier wave and \mathrm{m}$ for the modulating signal. The frequencies present in the modulated wave are

Options

A $\omega_c$ and $\sqrt{\omega_c^2+\omega_m^2}$
B $\omega_c, \omega_c+\omega_m$ and $\omega_c-\omega_m$
C $\omega_c$ and $\omega_m$
D $\omega_c$ and $\sqrt{\omega_c \omega_m}$

Correct answer

B. $\omega_c, \omega_c+\omega_m$ and $\omega_c-\omega_m$

Step-by-step solution

The frequencies present in amplitude modulated wave are : Carrier frequency

=\omega_c

Upper side band frequency

=\omega_c+\omega_m

Lower side band frequency

=\omega_c-\omega_m

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