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JEE Main 202628 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2026 · 28 January · Morning Shift · Physics · Current Electricity

For the two cells having same EMF E and internal resistance r , the...

For the two cells having same EMF EE and internal resistance rr, the current passing through the external resistor 6Ω6 \Omega is same when both the cells are connected either in parallel or in series. The value of internal resistance rr is ____\_\_\_\_ Ω\Omega.

Options

  1. A6
  2. B3
  3. C4
  4. D9

Correct answer

A. 6

Step-by-step solution

For series connection of two cells: Is=2E2r+6I_s = \frac{2E}{2r + 6}.
For parallel connection: Ip=Er/2+6=2Er+12I_p = \frac{E}{r/2 + 6} = \frac{2E}{r + 12}.
Given Is=IpI_s = I_p: 2E2r+6=2Er+12\frac{2E}{2r + 6} = \frac{2E}{r + 12}.
This gives 2r+6=r+122r + 6 = r + 12, so r=6Ωr = 6\Omega.
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