Two resistors of 100 each are connected in series with a 9 V battery. A voltmeter of 400 resistance is connected to measure the voltage drop across one of the resistors. The voltmeter reading is \_\_\_\_ V.

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Correct answer: C. 4

When the 400Ω voltmeter is connected in parallel with one 100Ω resistor, the equivalent resistance is

R_{eq} = \frac{100 \times 400}{500} = 80Ω

.
Total circuit resistance:

R_{total} = 100 + 80 = 180Ω

.
Circuit current:

I = 9/180 = 0.05

A.
Voltmeter reading (voltage across parallel combination):

V = 0.05 \times 80 = 4

V

Two resistors of 100 each are connected in series with a 9 V...

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