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JEE Main 20254 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2025 · 4 April · Morning Shift · Physics · Current Electricity

Current passing through a wire as function of time is given as...

Current passing through a wire as function of time is given as I(t)=0.02t+0.01 A\mathrm{I}(\mathrm{t})=0.02 \mathrm{t}+0.01 \mathrm{~A}. The charge that will flow through the wire from t=1st=1 s to t=2st=2 s is :

Options

  1. A0.06 C
  2. B0.02 C
  3. C0.07 C
  4. D0.04 C

Correct answer

D. 0.04 C

Step-by-step solution

q=∫idt∫02(0.02t+0.01)dt\begin{aligned} & \mathrm{q}=\int \mathrm{idt} \\ & \int_0^2(0.02 \mathrm{t}+0.01) \mathrm{dt}\end{aligned}
q=[0.02t22+0.01t]12=0.01(3)+0.01(1)=0.04C\begin{aligned} & \mathrm{q}=\left[0.02 \frac{\mathrm{t}^2}{2}+0.01 \mathrm{t}\right]_1^2 \\ & =0.01(3)+0.01(1) \\ & =0.04 \mathrm{C}\end{aligned}
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