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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2025 · 22 January · Morning Shift · Physics · Current Electricity

Sliding contact of a potentiometer is in the middle of the...

Sliding contact of a potentiometer is in the middle of the potentiometer wire having resistance R_p=1 as shown in the
Sliding contact of a potentiometer is in the middle of the potentiometer wire having resistance Rp=1ΩR_p=1 \Omega as shown in the figure. An external resistance of Re=2ΩR_e=2 \Omega is connected via the sliding contact. The electric current in the circuit is :

Options

  1. A0.9 A
  2. B1.35 A
  3. C0.3 A
  4. D1.0 A

Correct answer

D. 1.0 A

Step-by-step solution

The circuit can be considered as ∴Req =0.5+0.5×22+0.5=(510+1025)Ω=4550=910=0.9∴i=0.90.9=1A\begin{aligned} & \therefore \mathrm{R}_{\text{eq }}=0.5+\frac{0.5 \times 2}{2+0.5}=\left(\frac{5}{10}+\frac{10}{25}\right) \Omega \\ & =\frac{45}{50}=\frac{9}{10}=0.9 \\ & \therefore \mathrm{i}=\frac{0.9}{0.9}=1 \mathrm{ A}\end{aligned}
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