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JEE Main 20249 AprilEvening Shift

Exam: JEE Main
Year: 2024
Date: 9 April
Shift: Evening Shift
Subject: Physics
Chapter: Current Electricity

JEE Main 2024 · 9 April · Evening Shift · Physics · Current Electricity

To determine the resistance (R) of a wire, a circuit is designed...

To determine the resistance

(R)

of a wire, a circuit is designed below. The

V-I

characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of

R

is ______

\Omega

.

To determine the resistance (R) of a wire, a circuit is designed below. The V-I characteristic curve for this circuit

Correct answer

0

Step-by-step solution

\begin{aligned} & \text{ Req }=\frac{10^4 R}{10^4+R} \\ & E=4 V, I=2 m A \\ & I=\frac{E}{R e q} \Rightarrow 2 \times 10^{-3}=\frac{4\left(10^4+R\right)}{10^4 R} \\ & \Rightarrow 20 R=40000+4 R\end{aligned}

\begin{aligned} & 16 R=40000 \\ & R=2500 \Omega\end{aligned}

$

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