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JEE Main 20249 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
9 April
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2024 · 9 April · Morning Shift · Physics · Current Electricity

The current flowing through the 1 resistor is (n)/(10) A. The value...

The current flowing through the 1Ω1 \Omega resistor is n10\frac{n}{10} A. The value of nn is _________ The current flowing through the 1 resistor is (n)/(10) A. The value of n is _________

Correct answer

0

Step-by-step solution

y−52+y−02+y−x+101=0y−5+y+2y−2x+20=04y−2x+15=0….( (i) x−54+x−04+x−10−y1=0x−5+x+4x−40−4y=06x−4y−45=0..(i)−2x+4y+15=0..(ii)4x−30=0x=1524y−15+15=0y=0i=y−x+101i=0−7.5+101i=2.5A=n10An=25\begin{aligned} & \frac{y-5}{2}+\frac{y-0}{2}+\frac{y-x+10}{1}=0 \\ & y-5+y+2 y-2 x+20=0 \\ & 4 y-2 x+15=0 \quad \ldots .(\text{ (i) } \\ & \frac{x-5}{4}+\frac{x-0}{4}+\frac{x-10-y}{1}=0 \\ & x-5+x+4 x-40-4 y=0 \\ & 6 x-4 y-45=0 \quad . .(i) \\ & \frac{-2 x+4 y+15=0 . .(i i)}{4 x-30=0} \\ & x=\frac{15}{2} & 4 y-15+15=0 \\ & y=0 \\ & i=\frac{y-x+10}{1} \\ & i=\frac{0-7.5+10}{1} \\ & i=2.5 A=\frac{n}{10} A \\ & n=25\end{aligned}
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